Node:Unwarranted assumptions about storage, Next:Array out of bounds, Previous:Confusing foo++ and ++foo, Up:Run-time errors
Do not assume that the size of a structure is the sum of the sizes of its parts. The two may differ for various reasons; for example, the operating system may be aligning variables with specific addresses within the data structure. Furthermore, the elements of an array may not even be next to one another in memory.
This kind of code is always safe:
int my_array[3]; my_array[0] = 0; my_array[1] = 0; my_array[2] = 0;
This kind of code is not:
int my_array[3]; *my_array = 0; *(my_array + (1 * sizeof(int))) = 0; *(my_array + (2 * sizeof(int))) = 0;
While it is true that the variable my_array
used without its
square brackets is a pointer to the first element of the array, you
must not assume that you can simply calculate a pointer to the third
element with code like the following:
my_array + 2 * sizeof(int);
Do something like this instead:
&(my_array[2]);